python - Compare a bunch of integers to a variable in an if-statement -

python - Compare a bunch of integers to a variable in an if-statement -

i want compare s in for-loop bunch of numbers multiples of 5 , don't want write out of or's in-between. there easier way write this?

for s in range(0,50): lst = [] if s == 5,10,15,20,25,30,35,40,45: lst.append(" ") else: lst.append(letter) #letter defined before

of course, it's not right syntax way i've written , comes bunch of errors.

this in operator for1:

if s in (5, 10, 15, 20, 25, 30, 35, 40, 45):

in specific case however, see if number divisible 5:

if not s % 5: # or if s % 5 == 0:

also, need move line outside of loop:

lst = []

otherwise, lst redefined each iteration.

1in python 3.3 or greater, more efficient utilize set literal here instead of tuple literal:

if s in {5, 10, 15, 20, 25, 30, 35, 40, 45}:

the newer versions of python smart plenty recognize constants such this, evaluating them 1 time instead of each time encountered. thus, improve utilize set, has o(1) (constant) lookup time, rather tuple, has o(n) (linear) lookup time.

python if-statement comparison