c++ - Why does this double-free error happen? -

c++ - Why does this double-free error happen? -

i have base of operations , derived class:

in a.h:

//includes class { protected: static std::string a; //other dummy code };

in a.cpp

std::string a::a = "bar"; //other dummy code

in b.h:

#include "a.h" //other includes class b : public { public: int c; //other dummy code };

main.cpp:

#include "a.h" #include "b.h" int main() { printf("foo"); homecoming 0; }

now compile a.cpp , b.cpp 2 separate shared libraries "a.so" , "b.so" , link them against main.cpp. when run programme - quits corrupted-double-linked list error. running valgrind see there invalid free error. why happen?

i understand each .so file must have own re-create of static global variables, happens when derived class in different shared library while base of operations class in different shared library , there static variables in base of operations class? how memory allocated/destructed static variables in base of operations class, across libraries derived classes present?

i understand each .so file must have own re-create of static global variables

you understand incorrectly, unless linked a.o both a.so , b.so each .so file not have it's own re-create of static a::a. a.o should linked a.so , b.so shoould linked a.so, not a.o

c++ destructor double-free