python - letter count up algorithm -

python - letter count up algorithm -

first have german, sorry mistakes. here problem:

i have copied algorithm:

letters = list("123456") current in xrange(10): = [i in letters] y in xrange(current): = [x+i in letters x in a] = a[startpoint:] password in a: print password

from reply this: python brute forcefulness algorithm , want utilize algorithm seek out password against amateur brute-force. know there tests in net want create own test.

i finished brute-force-programm, found out algorithm generates 3 letters. 3 letters worked this:

aa, ba, ca, da, ea, fa, usw.

after possibilitys 2 letters trys this:

aaa, baa, caa, daa, eaa, faa, usw.

but if finished 3 letters, begin 2 letters again! why?

i don't realy understand algorithm do, know infinite formula , called recursion formula. understand tryed out this:

letters = list("123456") = [x+i in letters y+x in letters y in letters]

but producing "can't assign operator" error in other forum reply. based on tried out this:

letters = list("123456") = [x+i in letters y+x x in letters y in letters]

but syntax error. whats wrong code? , means "cant assign opperator" error, assign value opperator?

if want products of set utilize itertools product

import itertools min_pw_len,max_pw_len = 4,5 letters = list("123456") my_password = "1122" my_len in range(min_pw_len,max_pw_len): guess in itertools.product(letters,repeat=my_len): if "".join(guess) == my_password: print "found:",guess

as actual question syntax error

a = [x+i in letters y+x x in letters y in letters] ^this problem ... cannot (im not exclusively sure trying do)

im guessign want like

a2 = (x+y x in letters y in letters) #note generator not list a3 = (x+y x in a2 y in letters) a4 = (x+y x in a3 y in letters) ...

python algorithm for-loop brute-force