Sunday 15 June 2014

if statement - PHP If referrer exists show div... How? -



if statement - PHP If referrer exists show div... How? -

i show div table referrer title, when referrer exists, if doesn't exist - don't show it. need set "if exists" status after function. i'm beginner. far have function:

function getsitetitle(){ $refurl = (is_null($_server['http_referer'])) ? 'un know' : $_server['http_referer']; if($refurl != 'un know'){ $con = file_get_contents($refurl) or die (" can't open url referer "); $pattern = "/<title>(.+)<\/title>/i"; preg_match($pattern,$con,$match); $result = array($match[1],$refurl); homecoming $result; } else{ homecoming false; } } $info = getsitetitle(); echo "". $info[0];

i want show div table referrer title when referrer exists. if not exists don't show div.

$info = getsitetitle(); if ($info !== false) { echo "<div>ref title: {$info[0]}</div>"; }

php if-statement referrer

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