c - Print from pointer? -

c - Print from pointer? -

ok, have assignment gives me constant:

const char *suits[] = {"hearts", "diamonds", "clubs", "spades"};

basically table pointer points 4 words! simple right?

then have import each word table!

so create new table:

char table[30];

in main structure, , want somehow import within word "diamonds"! on pointer's table word on sec place. suits[1].

well when seek print sec word using command:

printf("%s", *suits[1]);

i error. using command

printf("%c", *suits[1]);

i "d", first letter. have ideas on how able print whole word "diamonds", , how can re-create table create in main form?

(i need re-create word suits[1] new table , able print table)

thank much!!!

i'm not clear on mean "copy table", on printing string, can help there.

executive summary: printf("%s", suits[0]); // prints diamonds what string in c, , memory like?

we have code:

const char *suits[] = {"hearts", "diamonds", "clubs", "spades"};

in memory is:

suits[0] -> pointer memory contains {'h', 'e', 'a', 'r', 't', 's', '\0'} suits[1] -> pointer memory contains {'d', 'i', 'a', 'm', 'o', 'n', 'd', 's', '\0'} ...

a string in c refers pointer null terminated piece of memory. when want print string, do:

printf("%s", <a pointer null terminated string>);

in case, pointer found @ suits[0], do:

printf("%s", suits[0]); thoughts on copying table.

if want store string "hearts" in array, perhaps you're looking for:

snprintf(table, sizeof(table), "%s", suits[0]);

or

strncpy(table, sizeof(table), suits[0]);

c pointers