python - replace string via re.sub() using a regular exression as replacer -

python - replace string via re.sub() using a regular exression as replacer -

string = "@ablue , @red , @gyellow, @yellow, @ggreen" new = re.sub('(@[a-z][a-z])', "########" , string)

i need regular look able check @ next 2 uppercase letters , remove @ , first uppercase character.cc

using capturing grouping , backreference:

>>> import re >>> string = "@ablue , @red , @gyellow, @yellow, @ggreen" >>> re.sub('@[a-z]([a-z])', r"\1" , string) 'blue , @red , yellow, @yellow, green'

\1 in substitution string replaced first capturing grouping (the sec uppercase letter).

note used r"raw string literal". otherwise, need escape \: "\\1"

alternative using positive lookahead assertion:

>>> re.sub('@[a-z](?=[a-z])', '' , string) 'blue , @red , yellow, @yellow, green'

python regex string