Why string inputs after integer input gets skipped in Java? -

Why string inputs after integer input gets skipped in Java? -

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scanner issue when using nextline after nextxxx [duplicate]

i trying input values of string , integer variables in java. if taking input of string after integer, in console string input skipped , moves next input.

here code

string name1; int id1,age1; scanner in = new scanner(system.in); //i can input name if input before integers system.out.println("enter id"); id1 = in.nextint(); system.out.println("enter name"); //problem here, name input gets skipped name1 = in.nextline(); system.out.println("enter age"); age1 = in.nextint();

this mutual problem, , happens because nextint method doesn't read newline character of input, when issue command nextline, scanner finds newline character , gives line.

a workaround one:

system.out.println("enter id"); id1 = in.nextint(); in.nextline(); // skip newline character system.out.println("enter name"); name1 = in.nextline();

another way utilize nextline wrapped integer.parseint:

int id1; seek { system.out.println("enter id"); id1 = integer.parseint(input.nextline()); } grab (numberformatexception e) { e.printstacktrace(); } system.out.println("enter name"); name1 = in.nextline(); why not scanner.next() ?

i not utilize scanner.next() because read next token , not total line. illustration next code:

system.out("enter name: "); string name = in.next(); system.out(name);

will produce:

enter name: mad scientist mad

it not process scientist because mad completed token per se. maybe expected behavior application, has different semantic code posted in question.

java