debugging - Debug Exercise for Java 1 -

debugging - Debug Exercise for Java 1 -

import java.util.*; import java.applet.*; import java.util.scanner; public class game { public static void main(string[] args){ system.out.println("i ready play!"); scanner input = new scanner(system.in); system.out.println("what's age?"); string userinput = input.nextline(); if (userinput < 13){ system.out.println("you allowed play @ own risk"); } else system.out.println("play on!"); } system.out.println("you @ iggy concert, , hear lyric 'are ready?, start running.'"); system.out.println("suddenly, iggy stops , says, 'who wants race me @ running?'"); scanner input = new scanner(system.in); system.out.println("do want race iggy on stage?"); string userinput = input.nextline(); if (userinput == yes){ "you , iggy start racing. it's neck , neck! win shoelace!"); } else system.out.println("oh no! iggy shakes head , sings 'i set pace, can race without pacing.'"); var feedback = prompt("rate game out of 10"); if(feedback > 8) { console.log("thank you! should race 1 time again @ next concert!"); } else { console.log("i'll maintain practicing coding , racing."); } } }

this assignment java 1 class in high school , have no thought how prepare of this. realize there ton of errors , pretty irrelevant me want larn java , class isn't teaching me help appreciated.

firstly start reading on java.util.scanner & read on string comparing ! not give reply hints!

some of errors : 1. need utilize .equals , not ==

string userinput = input.nextline(); if (userinput == yes) you need int not string read on interger.parseint(string)

string userinput = input.nextline(); if (userinput < 13) {}

what var , prompt ?

var feedback = prompt("rate game out of 10");

console not defines

console.log("thank you! should race 1 time again @ next concert!");

this defined twice.

scanner input = new scanner(system.in);

& on !!!

java debugging