java - How to use regex contains " with Pattern.compile -

java - How to use regex contains " with Pattern.compile -

i have regex :

url\(\s*(['"]?+)(.*?)\1\s*\)

which retrieves url css file .

i utilize code , error :

pattern p = pattern.compile("url\(\s*(['\"]?+)(.*?)\1\s*\)"); matcher m = p.matcher(csstext); while (m.find()) { println m.group() }

as can note add together \ esacpe " . in vain

you need utilize \\ instead of \ in java regex:

pattern p = pattern.compile( "url\\(\\s*(['\"]?+)(.*?)\\1\\s*\\)" ); 1st \ escaping string object 2nd \ escaping underlying regex engine

java regex